C Program to counts the occurrences of the number in the array - IProgramX

Q. Write a function, which accepts an integer array and an integer as parameters and counts the occurrences of the number in the array.

Program

#include <stdio.h>
int main()
{
    int arr[100], freq[100];
    int size, i, j, count;
    printf("Enter size of array: ");
    scanf("%d", &size);
    printf("Enter elements in array: ");
    for(i=0; i<size; i++)
    {
        scanf("%d", &arr[i]);
        freq[i] = -1;
    }
    for(i=0; i<size; i++)
    {
        count = 1;
        for(j=i+1; j<size; j++)
        {
            if(arr[i]==arr[j])
            {
                count++;
                freq[j] = 0;
            }
        }
        if(freq[i] != 0)
        {
            freq[i] = count;
        }
    }
    printf("\nFrequency of all elements of array : \n");
    for(i=0; i<size; i++)
    {
        if(freq[i] != 0)
        {
            printf("%d occurs %d times\n", arr[i], freq[i]);
        }
    }
    return 0;
}

Output:

Enter size of array: 5
Enter elements in array: 4
3
4
2
4

Frequency of all elements of array :
4 occurs 3 times
3 occurs 1 times
2 occurs 1 times