Q.Write a function, which accepts a character and integer n as parameter and displays the next n characters
Program
#include <stdio.h>
int display(char);
int main()
{
char ch,c;
printf("Enter character:");
scanf("%c", &ch);
display(ch);
}
int display(char ch)
{
int n,i;
printf("how many next char:");
scanf("%d",&n);
printf("\nYou entered:\t%c\n", ch);
printf("Next character :");
for(i=0;i<n;i++)
{
ch=ch+1;
printf("\t%c", ch);
}
return 0;
}
Output:
Enter character:r
how many next char:5
You entered: r
Next character : s t u v w
Program
#include <stdio.h>
int display(char);
int main()
{
char ch,c;
printf("Enter character:");
scanf("%c", &ch);
display(ch);
}
int display(char ch)
{
int n,i;
printf("how many next char:");
scanf("%d",&n);
printf("\nYou entered:\t%c\n", ch);
printf("Next character :");
for(i=0;i<n;i++)
{
ch=ch+1;
printf("\t%c", ch);
}
return 0;
}
Output:
Enter character:r
how many next char:5
You entered: r
Next character : s t u v w
2 Comments
Very good
ReplyDeleteBut why you not able to give next exercises of advance
ReplyDelete