Display content of the directory | PHP - IProgramX

by - IProgram X on - September 02, 2018

Q. Write program to read directory name from user and display content of the directory.

HTML File:

<html>
<form action="a3a2.php" method="POST">
<h1>Display directory contents</h1>
<br>
<h3>Enter directory name : <input type="text" name='d'></h3>
<pre>
<input type="submit" name="submit" value="submit">

</pre>
</form>

</body>
</html>

PHP Function:
NOTE: PHP function is saved as "a3a2.php"

<?php

$d=$_POST['d'];
$h=dir(".");
if(is_dir($d))
{
$h=opendir($d);
echo "<h3><B>Directory Contents";
echo "<br/>";

while(($file=readdir($h))!==false)

{
echo "<h3>$file<br/>";
}

closedir($h);
}
else
{
echo "<center><h2><center><u>Invalid Directory or Directory does not exist!!!</u></center></h2></center>";
}
?>

Output: