Q . Accept a single digit from the user and display it in words. For example, if digit entered is 9, display Nine
Program
#include<stdio.h>
#include<conio.h>
void main()
{
int ch;
printf("Enter Digit(0-9): ");
scanf("%d",&ch);
switch(ch)
{
case 0:
printf("Zero\n");
break;
case 1:
printf("one\n");
break;
case 2:
printf("Two\n");
break;
case 3:
printf("Three\n");
break;
case 4:
printf("Four\n");
break;
case 5:
printf("Five\n");
break;
case 6:
printf("Six\n");
break;
case 7:
printf("Seven\n");
break;
case 8:
printf("Eight\n");
break;
case 9:
printf("Nine\n");
break;
default:
printf("invalid digit\nPlease try again ....\n");
break;
}
}
Output:
Enter Digit(0-9): 6
Six
Program
#include<stdio.h>
#include<conio.h>
void main()
{
int ch;
printf("Enter Digit(0-9): ");
scanf("%d",&ch);
switch(ch)
{
case 0:
printf("Zero\n");
break;
case 1:
printf("one\n");
break;
case 2:
printf("Two\n");
break;
case 3:
printf("Three\n");
break;
case 4:
printf("Four\n");
break;
case 5:
printf("Five\n");
break;
case 6:
printf("Six\n");
break;
case 7:
printf("Seven\n");
break;
case 8:
printf("Eight\n");
break;
case 9:
printf("Nine\n");
break;
default:
printf("invalid digit\nPlease try again ....\n");
break;
}
}
Output:
Enter Digit(0-9): 6
Six
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