Q. Write a program to display all Armstrong numbers between 1 and 500. (An Armstrong number is a number such that the sum of cube of digits = number itself Ex. 153 = 1*1*1 + 5*5*5+ 3*3*3
Program
#include <stdio.h>
main()
{
int number, temp, digit1, digit2, digit3;
printf("Print all Armstrong numbers between 1 and 500:\n");
number = 001;
while (number <= 500)
{
digit1 = number - ((number / 10) * 10);
digit2 = (number / 10) - ((number / 100) * 10);
digit3 = (number / 100) - ((number / 1000) * 10);
temp = (digit1 * digit1 * digit1) + (digit2 * digit2 * digit2) + (digit3 * digit3 * digit3);
if (temp == number)
{
printf("\n Armstrong no is:%d", temp);
}
number++;
}
}
Output:
Print all Armstrong numbers between 1 and 500:
Armstrong no is:1
Armstrong no is:153
Armstrong no is:370
Armstrong no is:371
Armstrong no is:407
Program
#include <stdio.h>
main()
{
int number, temp, digit1, digit2, digit3;
printf("Print all Armstrong numbers between 1 and 500:\n");
number = 001;
while (number <= 500)
{
digit1 = number - ((number / 10) * 10);
digit2 = (number / 10) - ((number / 100) * 10);
digit3 = (number / 100) - ((number / 1000) * 10);
temp = (digit1 * digit1 * digit1) + (digit2 * digit2 * digit2) + (digit3 * digit3 * digit3);
if (temp == number)
{
printf("\n Armstrong no is:%d", temp);
}
number++;
}
}
Output:
Print all Armstrong numbers between 1 and 500:
Armstrong no is:1
Armstrong no is:153
Armstrong no is:370
Armstrong no is:371
Armstrong no is:407
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