C Program to Count total number of alphabets, digits and special characters - IProgramX

Q. Write a program to accept characters till the user enters EOF and count number of alphabets and digits entered

Program

#include <stdio.h>
#include <string.h>
#include <stdlib.h>
void main()
{
    char str[100];
    int alp, digit, splch, i;
    alp = digit = splch = i = 0;


       printf("\n\nCount total number of alphabets, digits and special characters :\n");
       printf("--------------------------------------------------------------------\n"); 
       printf("Input the string : ");
       gets(str);

    while(str[i]!='\0')
    {
        if((str[i]>='a' && str[i]<='z') || (str[i]>='A' && str[i]<='Z'))
        {
            alp++;
        }
        else if(str[i]>='0' && str[i]<='9')
        {
            digit++;
        }
        else
        {
            splch++;
        }

        i++;
    }

    printf("Number of Alphabets in the string is : %d\n", alp);
    printf("Number of Digits in the string is : %d\n", digit);
    printf("Number of Special characters or space in the string is : %d\n\n", splch);
}

Output:

Input the string : I'm a programmer
Number of Alphabets in the string is : 13
Number of Digits in the string is : 0
Number of Special characters or space in the string is : 3