Q. Write a function isEven, which accepts an integer as parameter and returns 1 if the number is even, and 0 otherwise. Use this function in main to accept n numbers and check if they are even or odd
Program
#include<stdio.h>
int isEven(int);
main()
{
int n,no,c;
int i;
printf("how many no.:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%d",&no);
c=isEven(no);
if(c==1)
printf("EVEN NO\n");
else
printf("ODD NO\n");
}
}
int isEven(int x)
{
if(x%2==0)
return 1;
else
return 0;
}
Output:
how many no.:3
5
ODD NO
7
ODD NO
6
EVEN NO
Program
#include<stdio.h>
int isEven(int);
main()
{
int n,no,c;
int i;
printf("how many no.:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%d",&no);
c=isEven(no);
if(c==1)
printf("EVEN NO\n");
else
printf("ODD NO\n");
}
}
int isEven(int x)
{
if(x%2==0)
return 1;
else
return 0;
}
Output:
how many no.:3
5
ODD NO
7
ODD NO
6
EVEN NO
1 Comments
This is a good app
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