Q. Accept initial velocity (u), acceleration (a) and time (t). Print the final velocity (v) and the distance (s) travalled . (Hint: v = u + at, s = u + at2)
Q. find distance with velocity and time and acceleration.
Program
#include<stdio.h>
void main()
{
int sec;
float distance , initial_velocity,velocity, acceleration;
printf("Enter the time in seconds \n");
scanf("%d",&sec);
printf("Enter the initial velocity \n");
scanf("%f", &initial_velocity);
printf("Enter the acceleration \n");
scanf("%f", &acceleration);
velocity = (initial_velocity + (acceleration * sec));
distance = (initial_velocity + (acceleration * (sec*sec)));\
printf(" Total velocity is %f",velocity);
printf("\n Total distance travelled is %f", distance);
}
Output:
Enter the time in seconds
60
Enter the initial velocity
5
Enter the acceleration
7
Total velocity is 425.000000
Total distance travelled is 25205.000000
Q. find distance with velocity and time and acceleration.
Program
#include<stdio.h>
void main()
{
int sec;
float distance , initial_velocity,velocity, acceleration;
printf("Enter the time in seconds \n");
scanf("%d",&sec);
printf("Enter the initial velocity \n");
scanf("%f", &initial_velocity);
printf("Enter the acceleration \n");
scanf("%f", &acceleration);
velocity = (initial_velocity + (acceleration * sec));
distance = (initial_velocity + (acceleration * (sec*sec)));\
printf(" Total velocity is %f",velocity);
printf("\n Total distance travelled is %f", distance);
}
Output:
Enter the time in seconds
60
Enter the initial velocity
5
Enter the acceleration
7
Total velocity is 425.000000
Total distance travelled is 25205.000000
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